Which of the following complex ions is expect | vedclass

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(B) complex ion absorbs visible light if it contains unpaired electrons in its $d$-orbitals,allowing for $d-d$ transitions.$1$. In $[Ti(en)_2(NH_3)_2]

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$[Cr(NH_3)_6]^{3+}$

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(B) complex ion absorbs visible light if it contains unpaired electrons in its $d$-orbitals,allowing for $d-d$ transitions.$1$. In $[Ti(en)_2(NH_3)_2]^{4+}$,$Ti$ is in the $+4$ oxidation state. $Ti^{4+} = [Ar] 3d^0$. No $d$-electrons,so no $d-d$ transition.$2$. In $[Cr(NH_3)_6]^{3+}$,$Cr$ is in the $+3$ oxidation state. $Cr^{3+} = [Ar] 3d^3$. It has $3$ unpaired electrons,allowing for $d-d$ transitions.$3$. In $[Zn(NH_3)_6]^{2+}$,$Zn$ is in the $+2$ oxidation state. $Zn^{2+} = [Ar] 3d^{10}$. Fully filled $d$-orbitals,no $d-d$ transition.$4$. In $[Sc(H_2O)_3(NH_3)_3]^{3+}$,$Sc$ is in the $+3$ oxidation state. $Sc^{3+} = [Ar] 3d^0$. No $d$-electrons,so no $d-d$ transition.Therefore,only $[Cr(NH_3)_6]^{3+}$ is expected to absorb visible light.

Complexes	No. of unpaired electrons
$A. [CrF_6]^{4-}$	$P. 5$
$B. [MnF_6]^{4-}$	$Q. 2$
$C. [Cr(CN)_6]^{4-}$	$R. 1$
$D. [Mn(CN)_6]^{4-}$	$S. 4$

Which of the following complex ions is expected to absorb visible light?
[At. nos. $Zn = 30$,$Sc = 21$,$Ti = 22$,$Cr = 24$]

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Complexes No. of unpaired electrons

$A. [CrF_6]^{4-}$ $P. 5$

$B. [MnF_6]^{4-}$ $Q. 2$

$C. [Cr(CN)_6]^{4-}$ $R. 1$

$D. [Mn(CN)_6]^{4-}$ $S. 4$

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Which of the following complex ions is expected to absorb visible light?[At. nos. $Zn = 30$,$Sc = 21$,$Ti = 22$,$Cr = 24$]